Complex Ratio

Algebra Level 2

Simplify x 2 + 1 x i . \large \frac{x^2 + 1}{x - i} .


Notation: i = 1 i=\sqrt{-1} denotes the imaginary unit .

x i x - i x + i x + i x + i + 1 2 x + \frac{i + 1}{\sqrt{2}} x i + 1 2 x - \frac{i + 1}{\sqrt{2}}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Chew-Seong Cheong
Jan 16, 2017

x 2 + 1 x i = ( x i ) ( x + i ) x i For x i = ( x i ) ( x + i ) x i = x + i \begin{aligned} \frac {x^2+1}{x-i} & = \frac {(x-i)(x+i)}{x-i} & \small \color{#3D99F6} \text{For }x \ne i \\ & = \frac {(\cancel{x-i})(x+i)}{\cancel{x-i}} \\ & = \boxed{x+i} \end{aligned}

I suppose to be precise it should be stated that this is only the case for x i x \ne i , as there would be a point of discontinuity at this value.

Brian Charlesworth - 4 years, 4 months ago

Log in to reply

Thanks. I have added a comment in the solution.

Chew-Seong Cheong - 4 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...