Complex Sum From Complex Nos

Algebra Level 2

i i = ? \large i \sqrt{i} = \ ?

Notation: i = 1 i =\sqrt {-1} is the imaginary unit .

1 + i 2 \frac{ -1 + i } { \sqrt{2}} i 3 2 \frac{ i - \sqrt{3 } } {2} 1 + i 2 \frac{ 1 + i } { \sqrt{2}} i + 3 2 \frac{ i + \sqrt{3} } { 2 }

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2 solutions

Elaaf Salem
Aug 2, 2016

1 = e i π -1 = e^{iπ}

i = e i π / 2 i = e^{i*π/2}

i = e i π / 4 \sqrt{i} = e^{i*π/4}

now we have : i i i \sqrt{i} = e i π / 2 e^{i*π/2} * e i π / 4 e^{i*π/4} = e i 3 π / 4 e^{i*3π/4}

e i x = c o s ( x ) + i s i n ( x ) e^{ix} = cos(x) + i sin(x)

e i 3 π / 4 = 1 / 2 + i 1 / 2 e^{i*3π/4} = -1 / \sqrt{2} + i * 1 / \sqrt{2}

= 1 / 2 ( 1 + i ) = 1 / \sqrt{2} (-1+i)

That is what i was saying

Md Zuhair - 4 years, 10 months ago
Md Zuhair
Jul 29, 2016

i r o o t i irooti can be written as iroot (cos pi/2 + isin pi/2) ...... And by simplyfing taking the Euler Form ... we get the ans.

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