Complex Tetration!

Algebra Level 4

Tetration is defined as

n a = a a a n {^{n}a} = \underbrace{a^{a^{\cdot^{\cdot^{a}}}}}_n

Find the value of

2 i . {^{2}i}.

Notation : i = 1 i =\sqrt{-1} denotes the imaginary unit .


The answer is 0.2079.

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2 solutions

Ronak Agarwal
Aug 18, 2014

We have 2 i = i i ^{ 2 }{ i }={ i }^{ i } .

Now we will use polar form of writing the complex numbers.

i = e i π 2 i={e}^{\frac{i\pi}{2}}

Using this we get :

i i = e i 2 π 2 = e π 2 {i}^{i}={e}^{\frac{{i}^{2}\pi}{2}}={e}^{\frac{-\pi}{2}}

Math Man
Aug 18, 2014

i^i=e^(-pi/2)

How did you get this result?

Sharky Kesa - 6 years, 9 months ago

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ln i can be defined as ln i =ln|i|+i arg(i)=(pi/2) i

Wanchun Shen - 6 years, 9 months ago

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