Complex z

Algebra Level pending

Solve the equation for complex number.

z = z + i z z = |z| + i|z|

Enter real part of sum of all the solutions.


The answer is 0.

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2 solutions

Let z = z e i α z=|z|e^{iα} . Then z e i α = 2 z e i π 4 z = 0 |z|e^{iα}=\sqrt 2 |z|e^{i\frac{π}{4}}\implies |z|=0

Chew-Seong Cheong
May 20, 2020

z = z + z i = z ( 1 + i ) z ( 1 i ) = z ( 1 + i ) ( 1 i ) z i z = 2 z Equating the imaginary part on both sides. z = 0 \begin{aligned} z & = |z| + |z|i \\ & = |z|(1+i) \\ z(1-i) & = |z|(1+i)(1-i) \\ z - iz & = 2|z| & \small \blue{\text{Equating the imaginary part on both sides.}} \\ \implies z & = 0 \end{aligned}

Therefore the sum of real part of all the solutions is 0 \boxed 0 .

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