Suppose and are real numbers and . Find the product .
Details and assumptions
is the imaginary unit, where .
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Equating the real and imaginary parts of the complex numbers gives us a system of linear equations to solve: { 4 x − 4 3 = 2 y − x 3 x + y = 2 x + 2 y + 5 Solving the first equation for y gives us y = 2 5 x − 4 3 . Substituting this expression in for y in the second equation yields 3 x + 2 5 x − 4 3 = 2 x + 5 x − 4 3 + 5 , and multiplying both sides by 2 to get rid of the fraction gives us 6 x + 5 x − 4 3 = 4 x + 1 0 x − 8 6 + 1 0 . This equation simplifies to 3 3 = 3 x , from which it follows that x = 1 1 . Hence, y = 2 5 5 − 4 3 = 6 , and the product x y must be 66.