Complicated?

From $\color{#D61F06}{\tan{\dfrac{\pi}{3}}=\sqrt{3}}$ and $\color{#3D99F6}{\sin{\dfrac{\pi}{4}}=\dfrac{1}{\sqrt{2}}}$

Thus,

$\begin{aligned}16\color{#D61F06}{\tan}^2{\color{#D61F06}{\dfrac{\pi}{3}}}\color{#3D99F6}{\sin}^4{\color{#3D99F6}{\dfrac{\pi}{4}}}=&\ 16(\color{#D61F06}{\sqrt{3}})^2\left(\color{#3D99F6}{\dfrac{1}{\sqrt{2}}}\right)^4\\=&\ 16(3)\left(\dfrac{1}{4}\right)\\=&\ 4(3)=\boxed{12}\end{aligned}$

16 tan^2 (pi/3) sin^4(pi/4) = (48)/4 =12