Component of net force

Classical Mechanics Level 1

A 1 kg 1 \text{ kg} standard body has an acceleration of 2.00 m/s 2 2.00 \text{ m/s}^{2} at 20. 0 ∘ 20.0 ^ \circ angle to the positive direction of the x x -axis. What is the approximate x x component of the net force acting on the body?

1.88 N 2.10 N 1.66 N 1.35 N

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Srinivasa Satti by Srinivasa Satti

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2 solutions

Fares Salem
Jun 13, 2014

Force = Mass Acceleration Cos(angle between the moving direction and the x-axis) which will give us 1 2 Cos(20`)=1.88 approx.

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Hello,

Fnett = ma

Fx = (1) ( 2 cos 20 ) =~ 1.88 N...

thanks...

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