composite figures area problem

Geometry Level 2

In the figure above, all arcs are semi-circles. The area of the red region is 12.5 3.125 π 12.5-3.125 \pi . The area of the blue region is 4.5 1.125 π 4.5-1.125 \pi . The area of the green region is 8 2 π 8-2\pi . What is the area of the yellow right triangle?


The answer is 6.

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2 solutions

Zico Quintina
Jul 3, 2018

Consider a region like the ones painted red, blue or green in the given diagram. Its area is the difference between the area of a rectangle and a semi-circle, and if the radius of the semicircle is r r , then the rectangle has dimensions 2 r × r 2r \times r . Thus the area such a region can be written as

2 r 2 1 2 π r 2 = r 2 2 ( 4 π ) 2r^2 - \dfrac{1}{2} \pi r^2 = \dfrac{r^2}{2} (4 - \pi)

Re-writing the given areas in this form, we get

A R E D = 12.5 3.125 π = 3.125 ( 4 π ) r R = 2.5 A B L U E = 4.5 1.125 π = 1.125 ( 4 π ) r B = 1.5 A G R E E N = 8 2 π = 2 ( 4 π ) r G = 2 \begin{array}{rlll} A_{RED} &= \ \ 12.5 - 3.125 \pi &= \ \ 3.125 (4 - \pi) & \implies & r_R = 2.5 \\ A_{BLUE} &= \ \ 4.5 - 1.125 \pi &= \ \ 1.125 (4 - \pi) & \implies & r_B = 1.5 \\ A_{GREEN} &= \ \ 8 - 2 \pi &= \ \ 2 (4 - \pi) & \implies & r_G = 2 \end{array}

Thus the yellow triangle is 3 - 4 - 5 \ 3 \ \text{-} \ 4 \ \text{-} \ 5\ and its area is 1 2 ( 3 ) ( 4 ) = 6 \dfrac{1}{2}(3)(4) = \boxed{6}

Hana Wehbi
Jul 6, 2018

Nice problem.

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