If n is a composite number, then 2^{n} - 1 is which of them?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
n is a composite , then let n = kl, where k,l are positive integers , k,l>1. Now. 2^{n} - 1 = 2^{kl} - 1= 2^{k}{l} - 1^{l}. We know, that for any positive integers x , y, (x^{y} - 1) is divisible by (x - 1 ). hence, 2^{n} - 1 is divisible by 2^{k} - 1 , which is greater than 1.Implies that 2^{n} - 1 is a composite number.