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Approximate molar mass of H = 1 For S = 3 2 , and O = 1 6
Molecular weight of H 2 S O 4 = 2 + 3 2 + 1 6 × 4 = 9 8 g m o l Presence of O 2 ( percentage ) = 9 8 6 4 × 1 0 0 % = 6 5 . 3 % Merry Christmas 🎅 🤶 🦌
Just curious, is it possible to answer correctly without knowing the mass of 1 mol of S? (Assumptions : this person had no way to access a PT, but still remembers that H = 1 and O = 16, and realizes that S is one of the first twenty in the table). I saw you provided the access above, so it's just a hypothetical question being asked here, okay?
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P O = 2 H + S + 4 O 4 O = 2 × 1 + 3 2 + 4 × 1 6 4 × 1 6 ≈ 6 5 . 3 %