Computing a Partial Derivative

Calculus Level 1

What is the partial derivative in the $y$ -direction of the function

$f(x,y) = \tan(xy)$

evaluated at the point $(x,y) = (1,\pi)?$

0

\frac{1}{\pi}

1

\pi

1 solution

展豪張
Mar 22, 2016

$\displaystyle\frac{\partial}{\partial y}f(x,y)=x\sec^2(xy)$
Putting in $(x,y)=(1,\pi)$ , answer $=(1)\sec^2((1)(\pi))=1$

does this mean that you just derivated x while helding y constant?

Bruno Martel - 1 year, 3 months ago