Concept of Rotation

In case of pure rolling the velocity of the point of contact of the object with respect to the surface should be zero

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True False Partly contradictory Cannot say

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1 solution

Caleb Townsend
Mar 8, 2015

Consider a point on a cylinder (of radius r r ) that is purely rolling forward with angular velocity ω \omega . Now follow its motion as the cylinder rolls. What is the translational velocity of this point relative to the surface it is rolling upon? v = r ω + r ω cos θ v = r \omega + r \omega \cos \theta where θ \theta is the angle between the upwards vertical and your chosen point, measured clockwise. When this point is the point of contact between the cylinder and the ground, θ = π . \theta = \pi. Therefore v 0 = r ω + ( 1 ) r ω = r ω r ω = 0 v_0 = r \omega + (-1)r \omega = r \omega - r \omega = \boxed{0} Note that this does not actually depend on the radius or angular velocity, as in this special case, it cancels out.

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