Concurrent Planes

2014 2014 planes are drawn in the infinite space such that they are all concurrent at exactly one point. Let M M be the maximum number of regions that these planes can divide space. Find the last three digits of M M .


The answer is 184.

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2 solutions

Michael Mendrin
Jul 4, 2014

This is the same as finding the number of regions n n great circles divide the surface of a sphere. The first great circle divides it into 2 2 regions. Thereafter, the ( n + 1 ) t h (n+1)th great circle will intersect n n great circles in 2 n 2n places, creating 2 n 2n arcs, which creates 2 n 2n additional regions. Thus, the formula is

2 + 2 ( 1 2 n ( n 1 ) ) = n 2 n + 2 2+2(\frac { 1 }{ 2 } n(n-1))={ n }^{ 2 }-n+2

For n = 2014 n=2014 , it works out to 4054184 4054184 , the last 3 3 digits being 184 184 .

One can check this out by tabulating the first few results

{ 2 , 4 , 8 , 14 , 22 , 32... } \{ 2,4,8,14,22,32...\}

In particular, after dividing the sphere into 8 8 regions with 3 3 great circles in the obvious way, note that with the 4 t h 4th great circle can only add 6 6 more regions, not 8 8 .

Amazing sir .........

Apoorv Padghan - 6 years, 10 months ago

Yep, that was the intended solution. Nice job.

Daniel Liu - 6 years, 11 months ago

Are you a professional mathematician?

A Former Brilliant Member - 6 years, 9 months ago

Horrible troll problem

Alex Segesta - 6 years, 7 months ago
Steven Zheng
Aug 27, 2014

Here's a great derivation of the formula used by Michael Mendrin. Cutting Spherical Surfaces with the Euler Characteristic

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