What is the volume of the double-cone if the volume of a cylinder that contains it is
?
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First, we assume that the height of the cylinder is h, therefore the height of the double cone is also h and the height of one cone is 1/2h
V of Cylinder =πr^2 h = 300 cm^3
V of Cone = (πr^2 x 1/2h)/3 = (πr^2 h)/6
V of Double Cone = 2 x(πr^2 h)/6 = (πr^2 h)/3
πr^2 h = 300 cm^3
V = (πr^2 h)/3, substitute the value
V = 300 cm^3/3
V = 100 cm^3