Three points A , B , and C in three-dimensional Euclidean space have their respective coordinates ( − 6 , 2 , − 4 ) , ( − 1 , 1 , − 2 ) , and ( − 2 , 2 , 1 ) . What is the measure of ∠ A B C ?
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You could also get BA and BC by shifting (translating) all three points over so that B is at the origin.
From Distance Formula,
A B = 3 0
B C = 1 1
A C = 4 1
A B 2 + B C 2 = A C 2
So ∠ B = 9 0 °
I messed up the calculation :(
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Taking the direction from origin to the points A, B and C, we can write them as position vectors: O A = − 6 i ^ + 2 j ^ − 4 k ^ O B = − i ^ + j ^ − 2 k ^ O C = − 2 i ^ + 2 j ^ + k ^ .
Now lets figure out the vectors B A , B C , which is: B A = O A − O B = − 5 i ^ + j ^ − 2 k ^ B C = O C − O B = − i ^ + j ^ + 3 k ^ .
Since the dot product of the vectors B A , B C is B A ⋅ B C = ( − 5 ) ( − 1 ) + ( 1 ) ( 1 ) + ( − 2 ) ( 3 ) = 0 , the vectors B A , B C are perpendicular.
Thus ∠ A B C = 9 0 ∘ . □