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All energy eigen states (stationary states) have the form ψ ( x , t ) = ϕ ( x ) e i ω t {\psi}(x,t) = {\phi}(x) e^{-i {\omega}t} , where ω {\omega} is the angular frequency so that ψ ( x , t ) 2 = ϕ ( x ) 2 \left |{\psi}(x,t) \right |^{2} = \left |{\phi}(x) \right |^{2} implying that probability is independent of time.

Let ψ 1 ( x ) {\psi}_{1}(x) and ψ 2 ( x ) {\psi}_{2}(x) be two non-degenerate states such that follow above condition ψ 1 ( x , t ) = ϕ 1 ( x ) e i ω 1 t {\psi}_{1}(x,t) = {\phi}_{1}(x) e^{-i {\omega}_{1}t}

ψ 2 ( x , t ) = ϕ 2 ( x ) e i ω 2 t {\psi}_{2}(x,t) = {\phi}_{2}(x) e^{-i {\omega}_{2}t}

Let ψ ( x , t ) {\psi}_{'}(x,t) = ψ 1 ( x , t ) {\psi}_{1}(x,t) + ψ 2 ( x , t ) {\psi}_{2}(x,t)

Question: Is the wave function ψ ( x ) {\psi}_{'}(x) a stationary state. Meaning is ψ ( x , t ) 2 \left |{\psi}_{'}(x,t) \right |^{2} = ϕ ( x ) 2 \left |{\phi}_{'}(x) \right |^{2}

Depends on ω {\omega} s and ψ {\psi} s Always Never

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