confusing
Algebra
Level
pending
If four numbers are in an arithmetic progression such that their sum is 50 and the greatest number is 4 times the smaller number,the find the ap. Enter your answer as the product of the terms
12000
16000
none of these
14000
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1 solution
Given that there are 4 numbers in the ap. Let them be a-3d ,a-d, a+d and a+3d sum=4a=50 therefore,a=25/2 It is also given that the greatest term , that is ,a+3d,is equal to 4 times times the smallest term , that is,a-3d therefore, a+3d=4(a-3d) By substituting the value of a and solving it ,we the value of d as 5/2 therefore the first term is a-3d , that is ,5 the second term is a-d , that is ,10 the third term is a+d, that is ,15 the fourth term is a+3d , that is ,20 therefore the product is 15000. Therefore the required answer is none of these.