Divide the cube root of 0.008/0.027 with the square root of 0.09/0.04. Add 5/9 to it.Multiply it with the square of the square of 3. Express that as the sum of two consecutive numbers.What is the square of the greater number?
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Pretty Easy(I mean piece of cake)
Cube root of 0.008/0.027 is 2/3 .... (i) Square root of 0.09/0.04 is 3/2 .... (ii) Divide (i) by (ii)
We get 4/9 Then 4/9+5/9=1 Square of square of 3 is 81 and 81*1=81 Now consecutive numbers are 40 & 41 Square of greater number '41' is ???