congruence....

What will be the remainder if (2^44)-1 is divided by 89 ?


The answer is 0.

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1 solution

Omkar Kulkarni
Dec 29, 2014

2 44 1 = ( 2 11 1 ) ( 2 11 + 1 ) ( 2 22 + 1 ) 2^{44}-1=(2^{11}-1)(2^{11}+1)(2^{22}+1)

2 11 1 2^{11}-1 happens to be a multiple of 89. That's all I can think of.

I've also done the problem in this manner. :D

Trishit Chandra - 6 years, 5 months ago

By Euler's Criterion ( 2 / 89 ) 2 44 ( m o d 89 ) (2/89)\equiv 2^{44}\pmod{\! 89} , which is 1 1 , since by Quadratic Reciprocity 89 ± 1 ( m o d 8 ) ( 2 / 89 ) = 1 89\equiv \pm 1\pmod{\!8}\,\Rightarrow\, (2/89)=1 .

mathh mathh - 6 years ago

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Ahh yes. Thanks! :D

Omkar Kulkarni - 6 years ago

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