Conic Sections: Challenge #7

Geometry Level 3

Sub-unit: Parabola

Let the parabola y = a x 2 + 2 x + 3 y = ax^{2} + 2x + 3 touches the line x + y 2 = 0 x+ y -2 =0 at a point P. If a line through P parallel to x-axis is drawn to meet y + 1 = x y + 1 = \mid x \mid at Q and R and the area of triangle OQR (where O is the origin) is A square units, then 9 A 11 \frac{9A}{11} is equal to


The answer is 8.

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1 solution

Pedro Saboya
Aug 27, 2020

Se x+y = 2 tangencia a parabola y=ax^2+3x+2, então a = 9/4.

Portanto, P = (-2/3, 8/3).

Daí, R, S são a intercessão de y = 8/3 e y+1 = |x|, ou seja, (+-11/3, 8/3).

Portanto, a área A = 2.1/2.(11/3)(8/3) = 88/9.

Assim, 9A/11 = 8.

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