Consecutive vs Odd and Even (Part 6)

Algebra Level 1

What inequality sign should we place inside the square box?

123 4 5678 246 8 3579 \large{1234^{5678} \quad {\huge\square} \quad 2468^{3579}}

There is more consecutive war here .

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3 solutions

Ryan Tamburrino
Aug 15, 2015

Note that 2468 = 2 1234 2468=2\cdot 1234 . Thus, we want to see if 123 4 5678 123 4 3579 = 123 4 2099 > 2 3579 \dfrac{1234^{5678}}{1234^{3579}} = 1234^{2099} > 2^{3579} . Clearly, we have 123 4 2099 > 102 4 2099 = ( 2 10 ) 2099 = 2 20990 > 2 3579 1234^{2099} > 1024^{2099} = (2^{10})^{2099} = 2^{20990} > 2^{3579} , hence the answer.

2^3579 *

Kobi Shiran - 5 years, 10 months ago

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Oops, didn't catch that! Fixed. I'll add some more lines to the solution.

Ryan Tamburrino - 5 years, 10 months ago
Caner Uler
Nov 29, 2015

Take the logarithm of both sides and then compare the numbers. The first one is bigger than the second one.

Iqbal Mohammad
Nov 30, 2015

This hold true for:

For a > 2 and n >0:

a^n > 2^n

Multiply both sides with a^n

(a^2n) > ( a^n) x (2^n)

Hence proved (a^2n) > ( 2a)^n

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