Consecutive Integers

let three consecutive integers be x, x +1, x + 2. given that,The sum of the first and the third of three consecutive integers is 136. so, x + x + 2 = 136 then x = 67. so, the value of the second integer is x +1 = 67 + 1 = 68

Let the three consecutive integers be $n-1\text{, }n\text{,}$ and $n+1\text{.}$ We are given that $n-1+n+1=2n=136$ , so $n\text{,}$ the second integer, is $\boxed{68}\text{.}$

the first integer is x and the third is y

the second integer is obviously some number in between these.

As it is consecutive, it is safe to say that the second integer equals:

$\frac{x + y}{2}$

This equals: $\frac{136}{2}$

Equals: 68