Two sets and of 4 consecutive positive integers have exactly one integer in common. Let
Find .
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We can write A a n d B as follows:
B : { n + ( n + 1 ) + ( n + 2 ) + ( n + 3 ) } and
A : { ( n + 3 ) + ( n + 4 ) + ( n + 5 ) + ( n + 6 ) } for n > 0 .
Note that each term in the second set is 3 more than the equivalent term in the first set. Since there are four terms, then the total differences will be 4 × 3 = 1 2