Consecutive logging

Algebra Level 2

Compute log 3 4 log 4 5 log 5 6 . . . log 728 729 \log_{3} {4}\cdot \log_{4} {5}\cdot \log_{5} {6}\cdot... \cdot \log_{728} {729}


The answer is 6.

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1 solution

Danish Ahmed
Jul 7, 2015

log b a = log a log b \log_{b}a = \dfrac{\log a}{\log b}

The expression =

log 4 log 3 log 5 log 4 . . . . . log 729 log 728 \dfrac{\log 4}{\log 3}\dfrac{\log 5}{\log 4} ..... \dfrac{\log 729}{\log 728}

log 729 log 3 = log 3 6 log 3 = 6 \dfrac{\log 729}{\log 3}=\dfrac{\log 3^6}{\log 3} = 6

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