Consecutive Square-Free Positive Integers

There are k k consecutive positive integers, each of which is square-free.

What is the maximum possible value of k k ?


Details and Assumptions:

  • A positive integer n n is square-free if there is no positive integer k > 1 k>1 such that k 2 n k^2 \Big|\, n .

  • After solving this, you may want to solve this .


The answer is 3.

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1 solution

X X
Oct 13, 2018

If 4 is a divisor of a number, then it is not square free.

Hence, the maximum of k k is smaller than 4.

A example 5 , 6 , 7 5,6,7 shows the maximum is 3.

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