Conservation of momentum.

Relevant wiki: Conservation of Momentum

The mass of the truck and car is $m_1 = 563 ~\text{kg}$ and $m_2 = 350 ~ \text{kg}$ respectively.

The condition for answer being yes: $p_1 = p_2 \implies m_1 u_1 + m_2 u_2 = (m_1 + m_2 )v'$ .

$\begin{aligned} u_1 = v & = u + at \\ & = 0 + 0.4 \times 75 ~~~~ [a = 0.4 ~\text{ms}^{-2}, t = 75 ~s ] \\ & = 30 ~\text{ms}^{-1}. \\ \end{aligned}$

• $u_2 = 0 ~ \text{ms}^{-1}$

• $v' = 16.85~ \text{ms}^{-1}$

The total momentum before the collision:

$\begin{aligned} p_1 & = m_1 u_1 + m_2 u_2 \\ & = 563 \times 30 + 350 \times 0 \\ & = 16890 ~\text{kg} ~\text{ms}^{-1} \\ \end{aligned}$

The total momentum after the collision:

$\begin{aligned} p_2 & = (m_1 + m_2)v' \\ & = (563 + 350)(16.85) \\ & = 15384.05 ~\text{kg} ~\text{ms}^{-1}\\ \end{aligned}$

We get $p_1 \ne p_2$ . Hence the answer is no.