A ball falls on a fixed inclined plane of inclination θ from a height of h above the point of impact, making a perfectly elastic collision.
If it hits the plane again at a distance of x h sin θ from the point of the first impact, find x . Assume the inclined surface to be frictionless.
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why is the x-component of g with respect to sin and not cos? and same for y component of g. why is it with respect to cos? is there a switch of right triangles?
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Sorry for my paintning skills. https://s8.hostingkartinok.com/uploads/images/2017/09/bca8b68db0fa9a57fd4b10a4969566fe.png
i don't understand why time = 2vy / gy
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At the time t = g y v y v y = 0 and a ball is on top of his trajectory (with respect to plane). A ball will fall from this point same time, so t u p = t d o w n = g y v y
Full time is the sum of this two times. t = g y 2 v y
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It is easier to solve this problem with respect to a plane. Then:
g x = g sin θ g y = g cos θ v x = 2 g h sin θ v y = 2 g h cos θ t = g y 2 v y = g cos θ 2 2 g h cos θ = 2 g 2 h S = v x t + 2 g x t 2 = 4 h sin θ + 4 h sin θ = 8 h sin θ x = 8