Consistent ?? Think again

Algebra Level pending

{ x 1 + x 3 = 1 x 2 + 2 x 3 = ω x 1 x 2 + 3 x 3 = 2 x 1 + x 2 x 3 = 1 ω \begin{cases} x_1 +x_3=1 \\ -x_2+2x_3=\omega \\ x_1 - x_2 + 3x_3=2 \\ x_1+x_2-x_3 =1-\omega \end{cases}

Consider the linear systems above, where ω \omega is an arbitrary real constant.

Determine the value(s) of ω \omega that results in a consistent system.

Note : If there's more than one value of ω \omega , then submit their sum as your answer.


The answer is 1.

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1 solution

Md Omur Faruque
Jul 13, 2015

Subtracting equation 1 from equation 3 we get, x 2 + 2 x 3 = 1 \boxed{-x_2 +2x_3} = 1

From equation 2 we get, x 2 + 2 x 3 = w \boxed{-x_2 +2x_3}= w

So, w = 1 \boxed{w=1}

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