An integer N is divisible by 14, 15, 16, and 17.
Then N must be divisible by which of the following numbers as well?
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14×15×16×17 = 57120
57120 not divisible by (25) , thus the answer is not ( 2 5 )
57120 not divisible by (26) , thus the answer is not ( 2 6 )
57120 not divisible by (27) , thus the answer is not ( 2 7 )
57120 divisible by (24) , thus the answer is ( 2 4 )
Almost correct. The way you have phrased this suggests that N = 5 7 1 2 0 , which is incorrect. Do you know how to rectify it?
Plus, the lowest common multiple of 14, 15, 16 and 17 is not 57120.
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Since N is divisible by 1 5 , it must also be divisible by 5 1 5 = 3 , and since N is divisible by 1 6 , it must also be divisible by 2 1 6 = 8 .
Therefore, since N is divisible by both 3 and 8 , it must also be divisible by 3 ⋅ 8 = 2 4 .