Consistently divisible

Number Theory Level pending

An integer N N is divisible by 14, 15, 16, and 17.

Then N N must be divisible by which of the following numbers as well?

24 25 26 27

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2 solutions

David Vreken
Feb 17, 2018

Since N N is divisible by 15 15 , it must also be divisible by 15 5 = 3 \frac{15}{5} = 3 , and since N N is divisible by 16 16 , it must also be divisible by 16 2 = 8 \frac{16}{2} = 8 .

Therefore, since N N is divisible by both 3 3 and 8 8 , it must also be divisible by 3 8 = 24 3 \cdot 8 = \boxed{24} .

Matin Naseri
Feb 17, 2018

14×15×16×17 = 57120 \text{14×15×16×17 = 57120}

57120 not divisible by (25) \text{57120 not divisible by (25)} , thus the answer is not ( 25 ) \boxed{\color{#D61F06}{(25)}}

57120 not divisible by (26) \text{57120 not divisible by (26)} , thus the answer is not ( 26 ) \boxed{\color{#D61F06}{(26)}}

57120 not divisible by (27) \text{57120 not divisible by (27)} , thus the answer is not ( 27 ) \boxed{\color{#D61F06}{(27)}}

57120 divisible by (24) \text{57120 divisible by (24)} , thus the answer is ( 24 ) \boxed{\color{#20A900}{(24)}}

Almost correct. The way you have phrased this suggests that N = 57120 N = 57120 , which is incorrect. Do you know how to rectify it?

Plus, the lowest common multiple of 14, 15, 16 and 17 is not 57120.

Pi Han Goh - 3 years, 3 months ago

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I try that make it correct.

Matin Naseri - 3 years, 3 months ago

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