Constant together

Calculus Level pending

If F ( k , m , n ) = 0 0 0 k m n e π ( x + y + z ) d x d y d z ( e 2 π x + 1 ) ( e 2 π y + 1 ) ( e 2 π z + 1 ) ( n 2 + 4 x 2 ) ( k 2 + 4 y 2 ) ( m 2 + 4 z 2 ) , F(k, m,n)= \int_0^{\infty}\int_0^{\infty}\int_0^{\infty}\frac{kmn e^{\pi(x+y+z)} dx dy dz}{(e^{2\pi x}+1)(e^{2\pi y}+1)(e^{2\pi z}+1)(n^2+4x^2)(k^2+4y^2)(m^2+4z^2)} , and lim k 0 lim m 0 lim n ( 1 d d m F ( k , m , n ) i = 1 n j = 1 i + 1 γ i j + 2 ζ ( j + 1 ) 1 ) Γ ( i j + 1 ) ) q n J = e e γ π G \lim_{k\to 0}\lim_{m \to 0} \lim_{n\to \infty} \left(1-\frac{d}{dm}F(k,m,n)\sum_{i=1}^{n}\sum_{j=1}^{i+1}\gamma^{i-j+2}\frac{\zeta(j+1)-1)}{\Gamma(i-j+1)}\right)^{qn}\cdot J=e^{e^{\gamma} \pi G} where k , m , n k,m,n are positive real numbers, q q and J J are positive integers, then find the value of J + q J+q .


Notation: γ \gamma and G G denote Euler-Mascheroni constant and Catalan's constant .


This problem is the variant version of A general integral and also it is shared proposed problem in Romanian Mathematical Magazine to prove the closed form .


The answer is 65.

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