Choose six points randomly and uniformly on a circle. Let these points be the vertices of a hexagon. What is the probability that the center of the circle lies in this hexagon?
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The answer is 1 − 6 × ( 2 1 ) 5 = 1 6 1 3 ≈ 0 . 8 1 2 5 . For an explanation, adjust my solution to this variant .