Contains the Center? 5

Probability Level pending

Choose seven points randomly and uniformly on a circle. Let these points be the vertices of a heptagon. What is the probability that the center of the circle lies in this heptagon?


The answer is 0.890.

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1 solution

Arjen Vreugdenhil
Dec 19, 2017

In general for an n n -gon, in order for the center of the circle not to lie inside, we need to have all n n points lie within an arc of 18 0 180^\circ . Let P a P_a be first point (in clockwise direction) on this arc. Then the probability that the other n 1 n-1 points lie within 18 0 180^\circ in clockwise direction from P a P_a is ( 1 2 ) n 1 (\tfrac12)^{n-1} . For point P a P_a there are n n choices. Thus there is probability n × ( 1 2 ) n 1 n\times (\tfrac12)^{n-1} that the center of the circle does not lie inside the n n -gon.

Finally, taking the complement, the probability of finding the center inside the n n -gon is 1 n × ( 1 2 ) n 1 = 2 n 1 n 2 n 1 . 1 - n\times (\tfrac12)^{n-1} = \frac{2^{n-1} - n}{2^{n-1}}. In the case n = 7 n= 7 , we find 57 / 64 57/64 .

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