1 + 1 ! 1 + 2 ! 1 + 3 ! 1 + 4 ! 1 + … What is the value of this continued fraction correct up to 2 decimal places?
This problem is a part of set nested radicals
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Applying the binomial theorem to the limit definition of e, one gets 1/0!+1/1!+1/2!+1/3!+1/4!+…
Therefore the answer is e.
The given series is the expansion of e x . Here x=1. Thus, the value of series is e 1 ⇒ 2.71
Python 2.7:
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The number is e (Euler's Number). It is a irrational number, so you cannot define its exact value but you can get close to it.
You can either get a rough value by calculating the value of first few fractions (This works because the value of each fraction starts decreasing as you move towards right and after a few calculations, the value almost becomes negligible) -
1 + 1 + 2 1 + 6 1 + 2 4 1 + 1 2 0 1 = 2 . 7 1 8 0 5 5 5 5 6
Or you can calculate a more accurate value of it using this formula -
( 1 + n 1 ) n
where n is a very large number. As n approaches infinity, the expression above approaches e .
Exactly.. e+2 XD
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By definition, e is given by the Taylor Expansion given in the question. Hence, answer is e , approximately 2 . 7 1 .