My Continued Fraction

Algebra Level 2

x = 2 + 1 2 + 1 2 + 1 2 + \large x=2+\frac { 1 }{ 2+\frac { 1 }{ 2+\frac { 1 }{2 + \ldots } } }

If x x is the solution to the nested fraction above, and it can be written as a + b a+\sqrt { b }

Express your answer as the sum of a + b a+b .


The answer is 3.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Isaiah Simeone
Sep 25, 2014

x = 2 + 1 2 + 1 2 + 1 . . . . . x=2+\frac { 1 }{ 2+\frac { 1 }{ 2+\frac { 1 }{ ..... } } }

x = 2 + 1 x x=2+\frac { 1 }{ x }

x 2 = 2 x + 1 { x }^{ 2 }=2x+1

x 2 2 x 1 = 0 { x }^{ 2 }-2x-1=0

x = 1 + 2 x=1+\sqrt { 2 }

A n s w e r = 3 Answer = 3

x 2 2 x 1 = 0 1 ± 1 1 × 1 = 1 ± 2 \displaystyle x ^ { 2 } - 2x - 1 = 0 \rightarrow 1 \pm \sqrt { 1 - 1 \times -1 } = 1 \pm \sqrt { 2 } .

Not x = 1 + 2 x = 1 + \sqrt { 2 } .

. . - 2 months, 2 weeks ago

I substituted it with the even quadratic formula.

. . - 2 months, 2 weeks ago
Curtis Clement
Feb 20, 2015

1 x 2 = x x 2 2 x 1 = 0 \frac{1}{x-2} = x \Rightarrow\ x^2 -2x-1 =0 ( x 1 ) 2 = 2 (x-1)^2 =2 N o w x > 0 s o \large Now \ x > 0 \ so x 1 = + 2 x-1 = +\sqrt{2} x = 1 + 2 \therefore\ x = 1 + \sqrt{2} a n s w e r = 3 \large answer =3

There is no proof that x x must be positive.

. . - 2 months, 2 weeks ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...