convergent or not infinity series!!!!!!

Calculus Level 1

Does ∑ n = 1 ∞ sin ⁡ n θ n 2 \displaystyle \sum_{n = 1}^{\infty} \frac{\sin n\theta}{n^2} converge?

No, it diverges. Yes, it converges.

Neo Strecker by Neo Strecker , 17, Denmark

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1 solution

Neo Strecker
Nov 11, 2019

it's convergent because sin ⁡ n θ n 2 ≤ 1 n 2 \frac{\sin n\theta}{n^2} \leq \frac{1}{n^2}

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