Convergent Sequence

Algebra Level 3

1 + 1 2 + 1 4 + 1 8 + 1 16 + + 1 2 n + = ? \large 1 + \dfrac 12 + \dfrac14 + \dfrac18 + \dfrac1{16} + \cdots + \dfrac1{2^n} + \cdots = \, ?


The answer is 2.

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1 solution

Kexin Zheng
Jun 27, 2016

This is a geometric sequence with a 1 = 1 a_1=1 and common ratio r = 1 2 r=\frac{1}{2} The sum of an infinite geometric series is a 1 1 r \frac{a_1}{1-r} Therefore, the sum is 1 1 1 2 \frac{1}{1-\frac{1}{2}} = 2 =\boxed{2}

You could also do it like this:

This series can be expressed as

1 2 x \frac { 1 }{ { 2 }^{ x } }

Now, the first and the second term add up to 3/2.

The first and the second and the third add up to 7/4.

The first and the second and the third and the fourth add up to 31/16.

You see that it gets closer and closer to two, right?

lim x 1 2 x = 2 \therefore \lim _{ x\rightarrow \infty }{ \frac { 1 }{ { 2 }^{ x } } =2 }

This means that the sum is 2.

alex wang - 4 years, 11 months ago

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