Convert it! (Problem 5)

$\begin{aligned} 1100101_2 & = \left(2^6 + 2^5 + 2^2+2^0\right)_{10} \\ & = (64+32+4+1)_{10} \\ & = \boxed{101}_{10} \end{aligned}$

Relevant wiki Binary numbers

$1100101$ in Base 2 converted to Base 10 is $1 \times 1 + 2 \times 0 + 4 \times 1 + 8 \times 0 + 16 \times 0 + 32 \times 1 + 64 \times 1 = \boxed{101}$ .