is a convex quadrilateral with and If the bisectors of the four internal angles are concurrent, find the value of .
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Since the point of concurrence is at the same distance from all four sides, a circle can be drawn having that point as center and touching the sides,as in the figure.Therefore A P = A S , B P = B Q , C R = C Q and D R = D S . Also the points on the angular bisector are equidistant from the sides.
Adding these four, we get A B + C D = A D + B C ;
i . e . , 3 + 7 = A D + 5 .
Hence A D = 5 .
Therefore ( A B + B C + C D + D A ) / D A = 4 .