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But doesnt this problem even depend upon the value of y ?????
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Well, only solution to this problem is x = 5 , y = 3 . If you'll change x , then y will vary but it won't be same for another value of x .
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Hmmm!!!!! Ok Ok !!!!! Thanx for the explanation!!!!!
x+y=8,x-y=2,thus consider x and y are two integers and 8/2=4 mean x=4,y=4 for first equation, then begin the second equation with 2/2=1,thus x=1 and y=1,so let's combine these two which mean x(first equation)+x(second equation) while y(first equation)-y(second equation)= x(4)+x(1)=5 while y(4)-y(1)=3
Add the equations to obtain:- 2 x = 1 0 . So, x = 5 .
Adding the two equations 2x=10, x=5
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Adding the two equations:
( x + y ) + ( x − y ) = 8 + 2
2 x = 1 0
x = 5 .