cool circle problem

The $\textit {Pythagorean triplet}$ in which biggest number is 10 can be found from the basic triplet $(3,4,5)$ by multiplying it with $2$ we get $\huge (6,8,10)$ Thus perimeter is $6+8+10=\boxed{24}$

AS we know genral formula of the pythagorian triplet is 2m,m^-1,m^+1 hypotenuse is equal to m^2+1 so M^2=9,m=3,so other two sides are of length 6and 8.So,perimeter is 6+8+10 =24