Find out (A + B + C + D) such that AB × CB = DDD, where AB and CB are two-digit numbers and DDD is a three-digit number.
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Just By Using Programming with VB 2013 :D .....
Private Sub Button1_Click
the results are : 2 7 3 9 ... so , a = 2 . b = 7 , c = 3 , d = 9
so , a + b + c + d = 2 + 3 + 7 + 9 = 2 1