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We know that 2 a ≥ 1 if a ≥ 0 .
Then 2 x 2 + 2 y 2 ≥ 2 since x 2 ≥ 0 and y 2 ≥ 0 .
But 1 + c o s 2 x ≤ 2 .
Then for the equation be need both LHS and RHS to be equal to 2.
Which gives x = y = 0