Cool equation

Algebra Level 3

How many ordered solutions ( x , y ) (x ,y) are there for the equation:

2 x 2 + 2 y 2 = 1 + c o s 2 x {2}^{{x}^{2}} + {2}^{{y}^{2}} = 1 + {cos}^{2} x

1 2 4 3

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1 solution

Adrian Neacșu
Apr 25, 2014

We know that 2 a 1 {2}^{a} \ge 1 if a 0 a\ge 0 .

Then 2 x 2 + 2 y 2 2 {2}^{{x}^{2}} + {2}^{{y}^{2}} \ge 2 since x 2 0 {x}^{2} \ge 0 and y 2 0 {y}^{2} \ge 0 .

But 1 + c o s 2 x 2 1 + {cos}^{2} x \le 2 .

Then for the equation be need both LHS and RHS to be equal to 2.

Which gives x = y = 0 x = y = 0

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