Cool Factorisation

Algebra Level 1

Find the solutions for x: 4 x 2 + 8 x + 3 = 0 4x^2+8x +3=0

-1.5,-0.5 -2,1 0.5,1 3,-1

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5 solutions

Mathh Mathh
Jan 3, 2015

Descartes' Rule of Signs says it can't have positive solutions. There was only one choice with all numbers negative.

nice and easy solution (unique)

Saron Mosazghi - 6 years, 5 months ago

nice solution @Mathh Mathh, didnot know about that rule thanks for sharing.

Mardokay Mosazghi - 6 years, 5 months ago

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I specifically made a simple problem to introduce brilliant community to it here .

mathh mathh - 6 years, 5 months ago

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thanks for the contribution, btw it was a nice problem .

Mardokay Mosazghi - 6 years, 5 months ago

Ha ha used a different solution , i used vieta formulas for sum and product so x 1 + x 2 = b / a x1+x2=-b/a and x 1 x 2 = c / a x1*x2=c/a by vieta so x 1 + x 2 = 2 x1+x2=-2 and product is x 1 x 2 = 3 / 4 x1*x2=3/4 and we see that 1.5 , . 5 -1.5,-.5 is the solution we need.

lol using vieta on such a problem

Saron Mosazghi - 6 years, 5 months ago
Mohammad Khaza
Jul 25, 2017

Descartes' Rule of Signs' says it can't have only positive solutions.that means if there is two solutions one must have to be negative

There was only one choice with all numbers negative.so,either one has to be negative or both has to be negative.both can not be positive

so,option 1 is the answer

Sunil Pradhan
Jan 2, 2015

Using factor method 4x² + 8x + 3 = 4x² + 6x + 2x + 3 = 0

2x(2x + 3) + 1(2x + 3) = 0

(2x + 1)(2x + 3) = 0

Then x = – 1/2 or – 3/2

Vaibhav Chauhan
Jan 1, 2015

4x^2+8x+3=0 => 4(x+1)^2-1=0 => x+1=1/2 and -1/2 => x= -1.5 and -0.5

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