Can all other numbers be expressed?

Which is the least possible integer greater than 7 7 , which cannot be expressed in the form 7 x + 3 y 7x+3y , where x x and y y are non-negative integers?

13 8 11 15

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2 solutions

Short Solution:

A quick glance at the options shows that for 8 8 , y y cannot be a non-negative integer (here, it is 1 3 \frac{1}{3} ).

Complete Solution:

The number in question, when divided by 7 7 , must leave a whole number with a remainder divisible by 3 3 . We can convert the options like so:

15 1 ( m o d 7 ) 15 \equiv 1 \pmod 7

8 1 ( m o d 7 ) 8 \equiv 1 \pmod 7

11 4 ( m o d 7 ) 11 \equiv 4 \pmod 7

13 6 ( m o d 7 ) 13 \equiv 6 \pmod 7

Modular Arithmetic

From first glance, 15 , 8 , 11 15, 8, 11 do not satisfy the requirements. ( 13 13 is possible since 6 6 is divisible by 3 3 .) However, we also need to take all of these ( m o d 3 ) \pmod 3 . Here we go:

15 0 ( m o d 3 ) 15 \equiv 0 \pmod 3

8 2 ( m o d 3 ) 8 \equiv 2 \pmod 3

11 2 ( m o d 3 ) 11 \equiv 2 \pmod 3

As can be seen, 15 15 is another possible choice (it can be made using 7 × 0 + 3 × 5 7 \times 0+3 \times 5 ). We are left with 11 11 and 8 8 . The smallest of them is 8 \boxed 8 .


Alternatively, use the Postage Stamp Problem / Chicken McNugget Theorem . By direct application of it, we find that every number greater than 12 12 can be expressed in the form 7 x + 3 y 7x+3y . Of the options, we only have 8 8 and 11 11 left. We can then easily find that 8 8 is the correct answer.

Nelson Mandela
Jul 3, 2015

given that x and y are positive, 8 is the least number which cannot be expressed as 7x+3y.

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