cool proving

Algebra Level 3

prove that .9999.............. = 1

.9999.... = x ----- and x = 1 (CPE) --1 = 1 (RPE) and .9999.. = 1 (SPE) [proven] by the means of process of estimation/rounding of numbers (it coneverges) [proven] let the value of .9999...1 = 1 and 9=9(what an obvious situation) [proven] .99999 = 1 ---------- 10 = 9.9999....... 9 = 9 (theory of approx) [proven]

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