Cool question

Algebra Level 2

The least value of function f ( x ) = a x 2 + b x + c , ( a > 0 ) f(x)=ax^2+bx+c, (a>0) exists at what value of x x ?

b 2 2 a \dfrac{b^2}{2a} b 4 a \dfrac{-b}{4a} b 2 4 a \dfrac{b^2}{4a} b 2 a \dfrac{-b}{2a}

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4 solutions

The least value of the function a x 2 + b x + c ax^2 + bx + c is 4 a c b 2 4 a \dfrac{4ac - b^2}{4a} .

The least value of the function OCCURS when x = b 2 a x = \dfrac{-b}{2a} . Please change the wording of the question

Shreyansh Vats
Apr 15, 2014

We can also comprehend the above problem in terms of the vertex of a parabola. Since it is asked to give the least value, the vertex of the parabola will be -b/2a.

The least value of the function x=-b/2a

Mohammad Mijan
Apr 8, 2014

Answer The least value is . X=-b/2a

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