coooool

$736 \equiv -5 \pmod {13}$ , hence $736^{32} \equiv (-5)^{32} \equiv (-1)^{16} \equiv 1 \pmod {13}$ .

$736^{12}=1 (mod ~ 13),~~~~736^3=5 (mod ~13),~~~736=8 (mod ~13)~~$ $\therefore ~ 736^{12+3+1}=1*5*8 (mod ~13)=1 (mod 13)\\ \therefore~736^{2*16}=1^2 (mod~ 13)=1 (mod~ 13).~~~~~~~~~~ \boxed{ 1 }$