A B C D . . . . a r e n p o i n t s i n a p l a n e w h o s e c o o r d i n a t e s a r e ( 1 , 2 ) ( 8 , 1 6 ) , ( 2 7 , 5 4 ) ( 6 4 , 1 2 8 ) ( 1 2 5 , 2 5 0 ) . . . ( 7 2 9 , 1 4 5 8 ) . A B i s b i s e c t e d i n t h e p o i n t G 1 ; G 1 C i s d i v i d e d a t G 2 i n t h e r a t i o 1 : 2 ; G 2 D i s d i v i d e d a t G 3 i n t h e r a t i o 1 : 3 ; G 3 E a t G 4 i n t h e r a t i o 1 : 4 a n d s o o n u n t i l a l l t h e p o i n t s a r e e x h a u s t e d . I f t h e c o o r d i n a t e o f t h e f i n a l p o i n t i s ( X Y ) . F i n d X Y .
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Nice Patrick Corn .Yes there is that way,too. But there's also a rigorous one.
All the points lie on the line y=2x
Quite easy as that paoint will also be on y = 2x...btw X = 225.
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Call me silly, but all the points in the construction are on the line y = 2 x . So the ratio you want is 2 .