Coordinates

Geometry Level pending

The lines with equations a x 2 y = c ax-2y=c and 2 x + b y = c 2x+by=-c are perpendicular and intersect at ( 1 , 5 ) (1, -5) . What is c c ?

-13 2 -8 13 8

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1 solution

Writing each equation in slope-intercept form, we get y = a 2 x 1 2 c y=\frac{a}{2}x-\frac{1}{2}c and y = 2 b x c b y=-\frac{2}{b}x-\frac{c}{b} . We observe the slope of each equation is a 2 \frac{a}{2} and 2 b -\frac{2}{b} , respectively. Because the slope of a line perpendicular to a line with slope m m is 1 m -\frac{1}{m} , we see that a 2 = 1 2 b \frac{a}{2}=-\frac{1}{-\frac{2}{b}} because it is given that the two lines are perpendicular. This equation simplifies to a = b a=b .

Because ( 1 , 5 ) (1, -5) is a solution of both equations, replace x x with 1 1 and y y with 5 -5 , and replace b b with a a , giving us a + 10 = c a+10=c and 2 5 a = c 2-5a=-c . Solving this system of equations, we will get c = 13 c =13 .

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