Coordination chemistry

Chemistry Level 3

No of spin free complex = m
No of spin paired complex = n

1) hexafluoridocobaltate (III) ion
2) hexaamminonickelate (II) ion
3) hexacyanoferrate (II) ion
4) hexacyanoferrate (III) ion
5) trioxalatocobaltate (III) ion
6) hexacyanocobaltate (II) ion
7) pentaaquanitrosoniumferrate (I) ion

Then n-m = ?


The answer is 1.

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1 solution

Nitish Deshpande
Oct 24, 2016

3, 4, 5, 6 are spin paired 1, 2, 7 are spin free

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